4x^2+5x-975=0

Solution for 4x^2+5x-975=0 equation:

4x^2+5x-975=0

a = 4; b = 5; c = -975;
Δ = b2-4ac
Δ = 52-4·4·(-975)
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15625}=125$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-125}{2*4}=\frac{-130}{8}
=-16+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+125}{2*4}=\frac{120}{8}
=15
$